Solving Surface Area Problems Lesson 9 4 Answer Key
Solving Surface Area Problems – Lesson 9, Question 4: Complete Answer Key and Step‑by‑Step Guide
When working through surface area problems, the key is to break the shape into familiar components, apply the right formulas, and keep track of units. Lesson 9, Question 4 is a classic example that tests understanding of how to calculate total surface area for a composite solid. Below is a full solution, followed by a detailed explanation of each step, common pitfalls, and extra practice problems.
1. Problem Statement
A rectangular prism has a length of 8 cm, a width of 5 cm, and a height of 3 cm. A right circular cylinder with a radius of 2 cm is attached to the top face of the prism, sharing the entire top face as its base. The cylinder extends upward by 4 cm. Calculate the total surface area of the resulting solid, excluding the bottom face of the prism.
2. Step‑by‑Step Solution
2.1 Identify the Components
| Component | Shape | Dimensions | Area Formula |
|---|---|---|---|
| Prism faces (excluding bottom) | Rectangular faces | 8 cm × 5 cm, 8 cm × 3 cm, 5 cm × 3 cm | (A = l \times w) |
| Cylinder lateral surface | Cylinder | Radius (r = 2) cm, Height (h = 4) cm | (A_{\text{lat}} = 2\pi r h) |
| Shared base (top of prism) | Circle | Radius (r = 2) cm | (A_{\text{base}} = \pi r^2) |
| Bottom face of prism | Rectangle | 8 cm × 5 cm | Excluded |
2.2 Compute Each Area
-
Prism lateral faces (excluding bottom)
- Front/back: (2 \times (8 \times 3) = 2 \times 24 = 48) cm²
- Left/right: (2 \times (5 \times 3) = 2 \times 15 = 30) cm²
- Top face (shared with cylinder): (8 \times 5 = 40) cm² (will be subtracted later)
Total prism area (without bottom) = (48 + 30 + 40 = 118) cm²
-
Cylinder lateral surface
(A_{\text{lat}} = 2\pi r h = 2\pi (2)(4) = 16\pi \approx 50.27) cm² -
Cylinder base (shared with prism)
(A_{\text{base}} = \pi r^2 = \pi (2)^2 = 4\pi \approx 12.57) cm²
2.3 Combine Areas, Removing Overlap
The top face of the prism is not part of the external surface because the cylinder covers it. Which means, subtract the area of the shared base once:
[ \text{Total Surface Area} = \underbrace{118}{\text{prism}} + \underbrace{16\pi}{\text{cylinder lateral}} - \underbrace{4\pi}_{\text{shared base}} = 118 + 12\pi ]
Numeric approximation:
[ 118 + 12\pi \approx 118 + 37.70 = 155.70 \text{ cm}^2 ]
Answer: (118 + 12\pi \ \text{cm}^2) (≈ 155.7 cm²)
3. Why the Formula Works
- Rectangular faces: Area equals length × width because rectangles are flat, two‑dimensional shapes.
- Cylinder lateral surface: Imagine cutting the curved surface into a rectangle of width equal to the height and length equal to the circumference ((2\pi r)). Multiplying gives the lateral area.
- Shared base subtraction: Since the top of the prism is covered by the cylinder, its area is hidden and should not be counted twice. Subtracting once removes the duplicate.
4. Common Mistakes to Avoid
| Mistake | What Happens | How to Fix |
|---|---|---|
| Counting the top face twice | Overestimates surface area | Subtract the shared base once |
| Using diameter instead of radius in cylinder formulas | Wrong area | Remember (r = \frac{\text{diameter}}{2}) |
| Mixing up units (cm vs. m) | Inconsistent results | Keep all dimensions in the same unit |
| Forgetting to exclude the bottom face | Slight overcount | Explicitly state exclusions in the problem |
5. Extra Practice Problems
-
Composite Solid A – A cube of side 6 cm has a hemispherical cap (radius 3 cm) glued to one face. Find the total surface area, excluding the base face of the cube.
-
Composite Solid B – A rectangular prism 10 cm × 4 cm × 2 cm has a right circular cylinder (radius 1 cm, height 5 cm) attached to one of its 10 cm × 2 cm faces. Compute the total surface area, excluding the bottom face of the prism.
-
Composite Solid C – Two right circular cylinders (radius 2 cm, height 6 cm each) are joined end‑to‑end. One cylinder’s top face is attached to a square plate (side 4 cm). Calculate the total surface area, excluding the bottom face of the plate.
Tip: For each problem, list the components, compute individual areas, then add/subtract as needed.
6. Quick Reference: Surface Area Formulas
| Shape | Formula | Variables |
|---|---|---|
| Rectangle | (A = l \times w) | (l) = length, (w) = width |
| Cylinder (lateral) | (A_{\text{lat}} = 2\pi r h) | (r) = radius, (h) = height |
| Cylinder (base) | (A_{\text{base}} = \pi r^2) | (r) = radius |
| Sphere | (A = 4\pi r^2) | (r) = radius |
| Cone (lateral) | (A_{\text{lat}} = \pi r l) | (r) = radius, (l) = slant height |
| Cone (total) | (A_{\text{total}} = \pi r (r + l)) |
7. Takeaway
By decomposing the solid into basic shapes, applying the correct formulas, and carefully handling overlaps, you can solve even complex surface area problems accurately. Practice the extra problems, and soon you’ll find these steps second nature.
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8. A Step‑by‑Step Worked Example
Let’s apply everything we’ve learned to a more elaborate composite shape: a rectangular prism (10 cm × 6 cm × 4 cm) with a right circular cylinder (radius 3 cm, height 8 cm) glued to one of its 10 cm × 4 cm faces. We’ll compute the total surface area, excluding the bottom face of the prism.
| Step | What to Do | Calculation | Result |
|---|---|---|---|
| **1. Consider this: 3\ \text{cm}^2). Practically speaking, | 4 faces × (10 cm × 6 cm) | (4 \times 60 = 240\ \text{cm}^2) | |
| 2. In practice, area = (\pi r^2 = \pi(3)^2 = 9\pi \approx 28. Now, the remaining four faces are exposed. Sum all exposed areas | (240 + 48\pi + 9\pi = 240 + 57\pi). So 8\ \text{cm}^2) | ||
| 3. Add the top base of the cylinder | The cylinder’s top is exposed. | (240 + 57\pi \approx 240 + 179.Add the lateral surface of the cylinder** | Cylinder lateral area = (2\pi r h = 2\pi(3)(8) = 48\pi). |
| 4. The top (6 cm × 10 cm) is covered by the cylinder, so it is also hidden. In real terms, identify exposed faces of the prism | The prism has 6 faces. | – | |
| **5. Still, | (48\pi \approx 150. The bottom (6 cm × 10 cm) is hidden. Add the base of the cylinder that sits on the prism** | This base is not exposed, so we do not add it. 1 = 419. |
Answer: The total exposed surface area is (240 + 57\pi \approx 419.1\ \text{cm}^2).
9. A Checklist for Future Problems
- List every component of the solid and draw a sketch if possible.
- Mark which faces are hidden by adjoining shapes.
- Compute each exposed area using the appropriate formula.
- Apply the inclusion‑exclusion principle: add all exposed parts, subtract any overlaps, and omit any fully covered faces.
- Verify dimensional consistency (all lengths in the same unit).
- Round only at the final step to preserve accuracy.
10. Final Thoughts
Surface area problems for composite solids can feel intimidating at first, but they’re really just a game of careful bookkeeping. By breaking the solid into familiar pieces, paying close attention to which surfaces are truly exposed, and systematically adding and subtracting areas, you’ll avoid the common pitfalls that trip up even seasoned geometry students.
Keep practicing with a variety of shapes—cylinders, cones, prisms, hemispheres, and their hybrids—and soon you’ll be able to tackle any surface‑area challenge with confidence. Happy computing!
10. Final Thoughts
Surface area problems for composite solids can feel intimidating at first, but they’re really just a game of careful bookkeeping. By breaking the solid into familiar pieces, paying close attention to which surfaces are truly exposed, and systematically adding and subtracting areas, you’ll avoid the common pitfalls that trip up even seasoned geometry students.
The key is to visualize the entire structure and meticulously track each component. Don't be afraid to sketch out your work – it often reveals hidden relationships and potential errors. Remember that the inclusion-exclusion principle is your friend; it helps ensure you're not double-counting or omitting crucial areas.
Keep practicing with a variety of shapes—cylinders, cones, prisms, hemispheres, and their hybrids—and soon you'll be able to tackle any surface‑area challenge with confidence. Happy computing!
9. A Checklist for Future Problems
- List every component of the solid and draw a sketch if possible.
- Mark which faces are hidden by adjoining shapes.
- Compute each exposed area using the appropriate formula.
- Apply the inclusion‑exclusion principle: add all exposed parts, subtract any overlaps, and omit any fully covered faces.
- Verify dimensional consistency (all lengths in the same unit).
- Round only at the final step to preserve accuracy.
10. Final Thoughts
Surface area problems for composite solids can feel intimidating at first, but they’re really just a game of careful bookkeeping. By breaking the solid into familiar pieces, paying close attention to which surfaces are truly exposed, and systematically adding and subtracting areas, you’ll avoid the common pitfalls that trip up even seasoned geometry students.
The key is to visualize the entire structure and meticulously track each component. Practically speaking, don't be afraid to sketch out your work – it often reveals hidden relationships and potential errors. Remember that the inclusion-exclusion principle is your friend; it helps ensure you're not double-counting or omitting crucial areas.
Keep practicing with a variety of shapes—cylinders, cones, prisms, hemispheres, and their hybrids—and soon you’ll be able to tackle any surface‑area challenge with confidence. Happy computing!
Conclusion:
Mastering surface area calculations for composite solids requires a methodical approach and a keen eye for detail. Which means by systematically dissecting the problem, identifying exposed surfaces, and applying the inclusion-exclusion principle, students can transform what might seem like a daunting task into a manageable and rewarding exercise in geometric understanding. Consistent practice and careful attention to precision are the keys to success in these types of problems.
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