Rewrite The Expression Using The Distributive Property

When you first meet the distributive property in algebra, it often feels like a simple trick to “get rid of parentheses.” Yet, once you master it, you’ll find that it’s a powerful tool for simplifying complex expressions, solving equations, and even proving identities. This article will walk you through the distributive property, show how to rewrite expressions step by step, and give you plenty of practice problems to reinforce your understanding.

What Is the Distributive Property?

The distributive property is a foundational rule in algebra that connects multiplication and addition (or subtraction). In its most common form, it states:

[ a \times (b + c) = a \times b + a \times c ]

You can also distribute a negative sign or a subtraction:

[ a \times (b - c) = a \times b - a \times c ]

The property works the same way for any real numbers (a), (b), and (c). It’s called “distributive” because it “distributes” the factor (a) across the terms inside the parentheses.

Why Is It Useful?

• Simplification: Turn a complicated expression into a sum of simpler terms.
• Factoring Out: When solving equations, you often need to factor a common term from both sides.
• Proofs: Many algebraic proofs rely on distributing to show equality.
• Polynomials: Expanding or simplifying polynomial expressions hinges on repeated use of the distributive property.

Step‑by‑Step Guide to Rewriting Expressions

Below is a systematic approach to rewriting any algebraic expression using the distributive property.

1. Identify the Parentheses

Look for groups of terms inside parentheses that are multiplied by a single factor outside the parentheses.

Example: [ 3(x + 4) ]

2. Apply the Property

Multiply the outer factor by each term inside the parentheses.

[ 3(x + 4) = 3 \times x + 3 \times 4 = 3x + 12 ]

3. Combine Like Terms (If Possible)

After distribution, you may end up with like terms that can be combined.

Example: [ 2(3x + 5) + 4x = (6x + 10) + 4x = 10x + 10 ]

4. Repeat as Needed

If the expression contains multiple sets of parentheses, repeat the process for each one.

Example: [ (2 - 3)(x + 7) = 2(x + 7) - 3(x + 7) = (2x + 14) - (3x + 21) = -x - 7 ]

5. Verify Your Work

Check that the simplified expression is equivalent to the original by plugging in a value for the variable (e.g., (x = 1)).

Original: ((2 - 3)(1 + 7) = (-1)(8) = -8)

Simplified: (-x - 7) with (x = 1) gives (-1 - 7 = -8). ✔️

Common Pitfalls and How to Avoid Them

Practical Examples

Example 1: Expanding a Polynomial

Rewrite ((x + 5)(x + 3)) using the distributive property.

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Solution:

1. Distribute (x) across ((x + 3)): [ x(x + 3) = x^2 + 3x ]
2. Distribute (5) across ((x + 3)): [ 5(x + 3) = 5x + 15 ]
3. Combine the results: [ (x^2 + 3x) + (5x + 15) = x^2 + 8x + 15 ]

Example 2: Simplifying a Complex Expression

Rewrite (4(2y - 3) - 3(2y + 1)).

Solution:

1. Distribute (4): [ 4(2y - 3) = 8y - 12 ]
2. Distribute (-3): [ -3(2y + 1) = -6y - 3 ]
3. Combine: [ (8y - 12) + (-6y - 3) = 2y - 15 ]

Example 3: Factoring Out a Common Term

Rewrite (6x^2 + 12x) by factoring out the distributive property.

Solution:

1. Identify the common factor (6x): [ 6x^2 + 12x = 6x(x + 2) ]
2. Verify: [ 6x(x + 2) = 6x^2 + 12x ]

FAQ: Common Questions About the Distributive Property

Q1: Can the distributive property be used with subtraction?
A1: Yes. The rule is (a(b - c) = ab - ac). Just treat subtraction as adding a negative.

Q2: Does the property work with fractions or negative numbers?
A2: Absolutely. The distributive property holds for all real numbers, including fractions and negatives.

Q3: What if there are nested parentheses?
A3: Work from the innermost parentheses outward, applying the distributive property at each level.

Q4: How do I remember the order of operations?
A4: PEMDAS/BODMAS: Parentheses/Brackets → Exponents/Orders → Multiplication and Division (left to right) → Addition and Subtraction (left to right). The distributive property is part of handling parentheses.

Practice Problems

1. Expand (5(3z - 2)).
2. Simplify (2(4x + 7) - 3(4x - 1)).
3. Factor (9y^2 - 12y).
4. Rewrite ((a - b)(a + b)).
5. Expand ((2x - 3)(x + 4)).

Answers:

1. (15z - 10)
2. (-2x + 17)
3. (3y(3y - 4))
4. (a^2 - b^2) (difference of squares)
5. (2x^2 + 5x - 12)

Conclusion

Mastering the distributive property is like learning a new language for algebra. It unlocks the ability to simplify, expand, and factor expressions with confidence. By consistently practicing the steps—identifying parentheses, applying the rule, combining like terms, and verifying your work—you’ll find that even the most daunting algebraic expressions become manageable. Keep solving problems, and soon rewriting expressions using the distributive property will feel as natural as breathing.